Compare Tuples based on the element, not the element & score

Set uses equals to compare if the set is already in the set. Redis
Sorted Sets are unique on the value, not the value with the score. The
Tuple.equals should return true when the elements are equal regardless
of what the score is. The score should be used when comparing to another
element in the set to see if it is < or >.
This commit is contained in:
Jon Bracy
2011-03-08 16:54:52 -05:00
parent 121af74972
commit 9dd1cff428

View File

@@ -4,7 +4,7 @@ import java.util.Arrays;
import redis.clients.util.SafeEncoder;
public class Tuple {
public class Tuple implements Comparable {
private byte[] element;
private Double score;
@@ -38,12 +38,22 @@ public class Tuple {
return false;
} else if (!Arrays.equals(element, other.element))
return false;
if (Double.doubleToLongBits(score) != Double
.doubleToLongBits(other.score))
return false;
return true;
}
public int compareTo(Tuple other) {
if (Arrays.equals(this.element, other.element))
return 0;
else
return this.score < other.getScore() ? -1 : 1;
}
public int compareTo(Object obj) {
if (getClass() != obj.getClass())
throw new ClassCastException();
return compareTo((Tuple) obj);
}
public Tuple(String element, Double score) {
super();
this.element = SafeEncoder.encode(element);